{"id":8734,"date":"2017-01-27t09:28:00","date_gmt":"2017-01-27t17:28:00","guid":{"rendered":"\/\/www.catharsisit.com\/hs\/?p=8734"},"modified":"2017-01-25t20:28:30","modified_gmt":"2017-01-26t04:28:30","slug":"ap-calculus-review-indefinite-integrals","status":"publish","type":"post","link":"\/\/www.catharsisit.com\/hs\/ap\/ap-calculus-review-indefinite-integrals\/","title":{"rendered":"ap calculus review: indefinite integrals"},"content":{"rendered":"
indefinite integrals make up a substantial part of what is covered on the ap calculus ab and bc exams. in this review article, we highlight a few concepts and techniques that you’ll need to be familiar with.<\/p>\n
there are two kinds of integrals, the definite and indefinite integrals. this article only discusses indefinite integrals. for a more general overview, including information about definite integrals, check out this review of integrals<\/a>.<\/p>\n an indefinite integral<\/strong> of a function f<\/em> is the most general antiderivative<\/strong> of f<\/em>.<\/p>\n <\/p>\n here, the function f<\/em> is any particular antiderivative for f<\/em>. that is, f<\/em>\u00a0‘<\/sup>(x<\/em>) = f<\/em>(x<\/em>). for example, f<\/em>(x<\/em>) = x<\/em>2<\/sup> is an antiderivative for f<\/em>(x<\/em>) = 2x<\/em>, since (x<\/em>2<\/sup>)’ = 2x<\/em>.<\/p>\n the c<\/em> is the constant of integration<\/strong>. it stands for any constant, and it must be part of your answer to an indefinite integral.<\/p>\n so for example,<\/p>\n <\/p>\n the reason we need to tack on that “\u00a0+\u00a0c<\/em>\u00a0” is so that we can describe absolutely every antiderivative for f<\/em>. remember the derivative rule for constant functions:<\/p>\n <\/p>\n therefore, if there is a particular function f<\/em>(x<\/em>) such that f<\/em>\u00a0‘(x<\/em>) = f<\/em>(x<\/em>), then for any constant c<\/em>, we have:<\/p>\n <\/p>\n thus the most general<\/em> antiderivative of f<\/em>(x<\/em>) would be f<\/em>(x<\/em>) + c<\/em>.<\/p>\n most everyone knows that you shouldn’t use a screwdriver to pound in a nail. and hammers do not help when driving in screws. in a similar way, you should be aware that each indefinite integral problem requires its own set of tools.<\/p>\n we’ll discuss a few integration tools, including the basic antiderivative rules, substitution, integration by parts, and partial fractions. other more advanced tools may be covered in future magoosh articles.<\/p>\n also, it’s important to realize that each technique requires quite a bit of practice before you can really get good at it. don’t expect to become an expert on the first day.<\/p>\nwhat’s the deal with the “\u00a0+\u00a0c<\/em>\u00a0” anyway?<\/h3>\n
indefinite integral techniques<\/h2>\n
basic antiderivative rules<\/h3>\n