{"id":2693,"date":"2014-09-12t09:00:48","date_gmt":"2014-09-12t09:00:48","guid":{"rendered":"\/\/www.catharsisit.com\/sat\/?p=2693"},"modified":"2015-04-14t21:00:03","modified_gmt":"2015-04-14t21:00:03","slug":"sat-video-friday-a-radical-cube","status":"publish","type":"post","link":"\/\/www.catharsisit.com\/hs\/sat\/sat-video-friday-a-radical-cube\/","title":{"rendered":"sat video friday: a radical cube"},"content":{"rendered":"

every now and then you\u2019ll see a cube on the sat in which a dotted line connects vertices on other ends of the cube. your job is to find that line. this usually requires that you have to use the pythagorean theorem twice (talk about cumbersome!). luckily, i\u2019m here to the rescue. when ever you are dealing with a cube\u2014and notice i said cube and not box\u2014the length of the line connecting two vertices that are at opposite corners of the cube is always s\u221a3, where s is the length of one side of the cube. <\/p>\n

yep, that\u2019s it. cool little formula to keep in mind. now the sat isn\u2019t always going to make such questions a cakewalk. so keeping in line with that devious spirit, i\u2019ve crafted a question involving this concept. <\/p>\n

watch the video below and see if you are able to get the right answer!
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